How would you factor: x^2-y^2+4y-4? My teacher got (x-y+2) (x+y-2). Thanks!

Let’s face it, factoring is an art, really. You might notice that y^2-4y+4 is a perfect square, namely (y-2)^2.

So then your original expression actually looks like x^2 - (y-2)^2, which is a difference of squares! So then you factor accordingly to end up with

(x - (y - 2))*(x + (y - 2)) = (x - y + 2)(x + y - x)

- H2

  1. maths-help posted this